Question:
Find the truth table for the function Y of A and B represented in the following figure.
Find the truth table for the function Y of A and B represented in the following figure.
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The AND gate receives A and B, the NOT gate inverts B, and the OR gate combines the two, so Y = A.B + B' (B bar). Evaluate for all four input pairs.
Updated On: Nov 4, 2026
A B Y 0 0 0 0 1 1 1 0 0 1 1 0 A B Y 0 0 1 0 1 0 1 0 1 1 1 1 A B Y 0 0 0 0 1 0 1 0 0 1 1 1 A B Y 0 0 0 0 1 1 1 0 1 1 1 1
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The Correct Option is B
Solution and Explanation
From the figure: A and B feed an AND gate giving \(A\cdot B\); B also feeds a NOT gate giving \(\bar B\). Both go to an OR gate, so \(Y=A\cdot B+\bar B\).
(A,B)=(0,0): \(0+1=1\).
(0,1): \(0+0=0\).
(1,0): \(0+1=1\).
(1,1): \(1+0=1\).
Truth table Y = 1, 0, 1, 1, which is option (2).
Answer: (2) the table with Y = 1, 0, 1, 1 for (A,B) = (0,0), (0,1), (1,0), (1,1)
(A,B)=(0,0): \(0+1=1\).
(0,1): \(0+0=0\).
(1,0): \(0+1=1\).
(1,1): \(1+0=1\).
Truth table Y = 1, 0, 1, 1, which is option (2).
Answer: (2) the table with Y = 1, 0, 1, 1 for (A,B) = (0,0), (0,1), (1,0), (1,1)
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