
In the given circuit, we have two diodes \( D_1 \) and \( D_2 \). The voltage across the diodes and the resistor is affected by the direction in which the diodes are connected and their characteristics.
- \( D_1 \) is forward-biased because its anode is connected to +5V, and the cathode is connected to the node where \( V_o \) is measured.
- \( D_2 \) is reverse-biased because its anode is connected to the node \( V_o \), and its cathode is connected to ground.
Since \( D_2 \) is reverse-biased, it will not conduct, and \( D_1 \) will conduct. Therefore, the output voltage \( V_o \) will be zero because the voltage drop across the conducting diode \( D_1 \) is almost zero in a forward-biased condition.
Thus, the output voltage is zero.
Therefore, the correct answer is (2) Zero.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,




What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)