Question

Find the odd one out (which of the following is not the Russian dramatist/novelist)

• A. Anton Chekhov
• B. Nikolai Gogol
• C. Maxim Gorki
• D. Arthur Miller

Hint:

Arthur Miller was an American playwright, whereas Chekhov, Gogol, and Maxim Gorky were famous Russian writers.

Answer 1

The Correct Option is D

Concept: Russian literature has produced some of the greatest dramatists and novelists in world history. Writers such as Anton Chekhov, Nikolai Gogol, and Maxim Gorky contributed enormously to drama, fiction, realism, and social literature. To identify the odd one out, it is important to determine which writer does not belong to Russian literature.

Step 1: Understanding Russian literary figures. Russian literature became famous because of:
• Psychological realism,
• Social criticism,
• Deep characterization,
• Philosophical and emotional themes. Many Russian writers influenced theatre and literature worldwide.

Step 2: Analyzing Anton Chekhov. Anton Chekhov was:
• A Russian playwright and short story writer,
• Famous for realistic drama,
• Known for plays such as ‘The Cherry Orchard' and ‘The Seagull'. Thus, he belongs to Russian literature.

Step 3: Analyzing Nikolai Gogol and Maxim Gorky.
• Nikolai Gogol was a Russian novelist and dramatist famous for works like ‘The Government Inspector'.
• Maxim Gorky was a Russian writer associated with socialist realism and dramatic literature. Both were important Russian literary personalities.

Step 4: Understanding why Arthur Miller is the odd one out. Arthur Miller was:
• An American playwright,
• Famous for plays like ‘Death of a Salesman' and ‘The Crucible',
• Not associated with Russian literature. Therefore, he is the odd one out among the given options.

Step 5: Final conclusion. Since Anton Chekhov, Nikolai Gogol, and Maxim Gorky were Russian literary figures while Arthur Miller was American, the correct answer is: \[ \boxed{\text{Arthur Miller}} \]