Question

Find the distance of the point \( (1,-2,3) \) from the \(yz\)-plane.

• A. \(0\)
• B. \(1\)
• C. \(2\)
• D. \(3\)

Hint:

For coordinate planes: Distance from \(yz\)-plane \(= |x|\) Distance from \(xz\)-plane \(= |y|\) Distance from \(xy\)-plane \(= |z|\)

Answer 1

The Correct Option is B

Concept: The \(yz\)-plane is defined by the equation \(x = 0\). The perpendicular distance of a point \( (x, y, z) \) from the \(yz\)-plane is equal to the absolute value of its \(x\)-coordinate. \[ \text{Distance} = |x| \]

Step 1: Identify the \(x\)-coordinate of the given point. The point is: \[ (1,-2,3) \] Thus, \[ x = 1 \]

Step 2: Apply the distance formula from the \(yz\)-plane. \[ \text{Distance} = |x| \] \[ \text{Distance} = |1| = 1 \] Hence, the distance of the point from the \(yz\)-plane is: \[ \boxed{1} \]