Question

Find the correct matches of the substances, given in Column I, from their characteristic properties given in Column II.

• A. W = C \quad X = D \quad Y = A \quad Z = B
• B. W = B \quad X = D \quad Y = C \quad Z = A
• C. W = A \quad X = C \quad Y = B \quad Z = D
• D. W = D \quad X = C \quad Y = A \quad Z = B

Hint:

The oxidation states of metals and non-metals in compounds can greatly influence their reactivity and stability. For example, in the case of Sn, the +3 oxidation state is highly oxidizing.

Answer 1

The Correct Option is A

- W = T1 (Titanium) Titanium (\(Ti_1\)) is known to decompose steam to form its oxide and dihydrogen gas. This matches with statement A, so W = (C) - X = CCl₄ (Carbon tetrachloride) Carbon tetrachloride (\(CCl_4\)) is a tetrahedral molecule consisting of twenty 6-membered rings and twelve 5-membered rings. This matches with statement B, so X = (D) - Y = Sn (Tin) Tin (\(Sn\)) in its +3 oxidation state is highly oxidizing. This matches with statement C, so Y = (A) - Z = C₆₀ (Buckminsterfullerene) \(C_{60}\), also known as Buckminsterfullerene, is an electron-precise species and does not act as either an electron donor or acceptor. This matches with statement D, so Z = (B) Thus, the correct matching is W = C, X = D, Y = A, Z = B, which corresponds to option (A)