Question:

The product formed in the following reaction is:

Show Hint

HBr + Peroxide \(\Rightarrow\) Anti-Markovnikov addition through free radical mechanism.
Updated On: May 20, 2026
  • FigA
  • FigB
  • FigC
  • FigD
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation


Concept: Addition of HBr in presence of peroxide follows anti-Markovnikov rule through free radical mechanism.

Step 1: Understanding peroxide effect.

In presence of benzoyl peroxide: \[ HBr \] adds via free radical pathway. Bromine radical attacks the double bond first.

Step 2: Stability of radical intermediate.

If bromine adds to terminal carbon: \[ \text{benzylic radical forms} \] Benzylic radicals are highly stable due to resonance. Therefore bromine attaches to the carbon farther from benzene ring.

Step 3: Final product formation.

Hydrogen attaches to benzylic carbon and bromine attaches to adjacent carbon. Thus product formed is: \[ HO-C_6H_4-CH_2-CH(Br)-CH_3 \]
Was this answer helpful?
0
0