Step 1: Calculate the number of pages in logical address space.
The logical address space is 32 KB and the page size is 4 KB. The number of pages is:
\[
\frac{32 \, \text{KB}}{4 \, \text{KB}} = 8 \, \text{pages}.
\]
Step 2: Calculate the number of page frames in physical memory.
The physical memory size is 64 KB and the page size is 4 KB. The number of page frames is:
\[
\frac{64 \, \text{KB}}{4 \, \text{KB}} = 16 \, \text{page frames}.
\]
Step 3: Conclusion.
Thus, the number of pages in the logical address space is 8, and the number of page frames in physical memory is 16. Hence, the correct answer is **(3) 8, 16**.
