Considering the above reaction, X and Y respectively are :
Considering the above reaction, X and Y respectively are :
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The Correct Option is B
Solution and Explanation
Step 2: The diazonium ion is a weak electrophile and attacks the activated ring of N,N-dimethylaniline (azo coupling). The strongly activating \(\mathrm{-N(CH_3)_2}\) group directs to the para position (less hindered), giving 4-(N,N-dimethylamino)azobenzene, \(\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}N(CH_3)_2}\) (Y).
So X = benzenediazonium chloride and Y = the para-coupled azo compound, option (2).
Answer: (2) X = C6H5N2+Cl-, Y = p-(dimethylamino)azobenzene
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