Concept:
A system of linear equations represented by \( AX = B \) can be solved using various methods such as Gaussian elimination, Cramer's rule (if square), or by identifying dependencies between the equations. In an overdetermined system (more equations than variables), a solution only exists if the additional equations are consistent with the primary ones.
Step 1: Extract the equations and identify redundancies.
From the matrix multiplication, we obtain four linear equations:
• \( x + 3y + 2z = 1 \)
• \( 2x + 2y - 3z = 1 \)
• \( 4x + 4y - 6z = 2 \)
• \( 2x + 5y + 2z = 1 \)
Observation: Equation (3) is simply \( 2 \times \) Equation (2), meaning it provides no new information and the system is consistent so far.
Step 2: Solve the system using elimination.
Subtracting Equation (2) from Equation (4):
\[ (2x + 5y + 2z) - (2x + 2y - 3z) = 1 - 1 \]
\[ 3y + 5z = 0 \quad \Rightarrow \quad y = -\frac{5z}{3} \quad \cdots (5) \]
Now, substitute \( y \) into Equation (1):
\[ x + 3\left(-\frac{5z}{3}\right) + 2z = 1 \quad \Rightarrow \quad x - 5z + 2z = 1 \quad \Rightarrow \quad x = 1 + 3z \quad \cdots (6) \]
Substitute both \( x \) and \( y \) back into Equation (2):
\[ 2(1 + 3z) + 2\left(-\frac{5z}{3}\right) - 3z = 1 \]
\[ 2 + 6z - \frac{10z}{3} - 3z = 1 \quad \Rightarrow \quad 3z - \frac{10z}{3} = -1 \]
\[ \frac{9z - 10z}{3} = -1 \quad \Rightarrow \quad -z = -3 \quad \Rightarrow \quad \mathbf{z = 3} \]
Step 3: Calculate \( y \) and the final expression.
Using \( z = 3 \) in Equation (5):
\[ y = -\frac{5(3)}{3} = \mathbf{-5} \]
The question asks for the value of \( y^2 + z^2 \):
\[ y^2 + z^2 = (-5)^2 + (3)^2 = 25 + 9 = 34 \]