Question:
Consider the following
\[
\begin{aligned}
\text{I.} \quad & \text{1-Bromo-1-phenylpropane} \\
\text{II.} \quad & \text{1-Bromo-3-}\mathit{n}\text{-butyl-2-methylbenzene}
\end{aligned}
\]
Bromides I and II are classified respectively as
Consider the following
\[
\begin{aligned}
\text{I.} \quad & \text{1-Bromo-1-phenylpropane} \\
\text{II.} \quad & \text{1-Bromo-3-}\mathit{n}\text{-butyl-2-methylbenzene}
\end{aligned}
\]
Bromides I and II are classified respectively as
Show Hint
\textbf{Benzylic halide:} Halogen attached to the carbon adjacent to a benzene ring.
\textbf{Aryl halide:} Halogen directly attached to the benzene ring.
Updated On: Jul 9, 2026
- Benzyl ; Aryl
- Aryl ; Aryl
- Primary ; Benzyl
- Aryl ; Primary \bigskip
Show Solution
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The Correct Option is A
Solution and Explanation
Step 1: Classify Bromide I.
The structure of 1-bromo-1-phenylpropane is
\[
\mathrm{C_6H_5-CH(Br)-CH_2-CH_3}
\]
Here, the bromine atom is attached to the carbon adjacent to the benzene ring (benzylic carbon).
Hence, Bromide I is a
\[
\boxed{\text{Benzyl bromide}.}
\]
Step 2: Classify Bromide II. In 1-bromo-3-n-butyl-2-methylbenzene, the bromine atom is directly attached to the benzene ring. Such compounds are classified as \[ \boxed{\text{Aryl halides}.} \]
Step 3: Final conclusion. Therefore, \[ \boxed{\text{I -- Benzyl,\qquad II -- Aryl}} \] Hence, the correct option is \(\boxed{(A)}\).
Step 2: Classify Bromide II. In 1-bromo-3-n-butyl-2-methylbenzene, the bromine atom is directly attached to the benzene ring. Such compounds are classified as \[ \boxed{\text{Aryl halides}.} \]
Step 3: Final conclusion. Therefore, \[ \boxed{\text{I -- Benzyl,\qquad II -- Aryl}} \] Hence, the correct option is \(\boxed{(A)}\).
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