Question:
Consider the elements with atomic numbers \(Z=8,9,11,19\) and \(20\). The number of ionic compounds possible with the elements having these atomic numbers is
Consider the elements with atomic numbers \(Z=8,9,11,19\) and \(20\). The number of ionic compounds possible with the elements having these atomic numbers is
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Ionic compounds usually form between metals and non-metals.
Updated On: May 7, 2026
- \(6\)
- \(5\)
- \(10\)
- \(8\)
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The Correct Option is A
Solution and Explanation
Concept:
Ionic compounds are generally formed between metals and non-metals.
Step 1: Identify the given elements: \[ Z=8 \Rightarrow O \] \[ Z=9 \Rightarrow F \] \[ Z=11 \Rightarrow Na \] \[ Z=19 \Rightarrow K \] \[ Z=20 \Rightarrow Ca \]
Step 2: Non-metals are: \[ O,\ F \]
Step 3: Metals are: \[ Na,\ K,\ Ca \]
Step 4: Ionic compounds are possible between each metal and each non-metal. \[ \text{Number of combinations}=3\times 2=6 \] \[ \boxed{6} \]
Ionic compounds are generally formed between metals and non-metals.
Step 1: Identify the given elements: \[ Z=8 \Rightarrow O \] \[ Z=9 \Rightarrow F \] \[ Z=11 \Rightarrow Na \] \[ Z=19 \Rightarrow K \] \[ Z=20 \Rightarrow Ca \]
Step 2: Non-metals are: \[ O,\ F \]
Step 3: Metals are: \[ Na,\ K,\ Ca \]
Step 4: Ionic compounds are possible between each metal and each non-metal. \[ \text{Number of combinations}=3\times 2=6 \] \[ \boxed{6} \]
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