Question:

Consider free electron gas, the order of excitation energy for an electron to jump from level \(1\) to level \(2\) is:

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Thermal excitation energy is generally of the order of \(k_B T\).
Updated On: May 19, 2026
  • \(2k_B T\)
  • \(\dfrac{k_B T}{2}\)
  • \(k_B T\)
  • \(\dfrac{3}{2}k_B T\)
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The Correct Option is C

Solution and Explanation

Concept:
In a free electron gas, thermal excitation energy is of the order of thermal energy.

Step 1: Thermal energy scale.

The characteristic thermal energy scale is: \[ k_B T \] where, \[ k_B=\text{Boltzmann constant} \] \[ T=\text{absolute temperature} \]

Step 2: Excitation energy.

For an electron to jump from a lower energy level to a higher energy level due to thermal excitation, the energy involved is generally of the order of: \[ k_B T \]

Step 3: Final answer.
\[ \therefore \text{Correct Answer is (C)} \]
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