Question:
Consider \(\dfrac{x}{2}+\dfrac{y}{4}\ge1\) and \(\dfrac{x}{3}+\dfrac{y}{2}\le1,\; x,y\ge0\). Then number of possible solutions are
Consider \(\dfrac{x}{2}+\dfrac{y}{4}\ge1\) and \(\dfrac{x}{3}+\dfrac{y}{2}\le1,\; x,y\ge0\). Then number of possible solutions are
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Graphical method is easiest for linear inequalities.
Updated On: Mar 24, 2026
- Zero
- Unique
- Infinite
- None of these
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The Correct Option is A
Solution and Explanation
Step 1: Plot both inequalities in first quadrant.
Step 2: Regions do not overlap.
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