Question:
Compare the relative stability of given carbocations.
\(\text{CH}_{3}\text{-}\text{C}^{+}\text{-(CH}_{3})_{2}\) (I) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H-CH}_{3}\) (II) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H}_{2}\) (III)
Compare the relative stability of given carbocations.
\(\text{CH}_{3}\text{-}\text{C}^{+}\text{-(CH}_{3})_{2}\) (I) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H-CH}_{3}\) (II) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H}_{2}\) (III)
\(\text{CH}_{3}\text{-}\text{C}^{+}\text{-(CH}_{3})_{2}\) (I) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H-CH}_{3}\) (II) \(\text{CH}_{3}\text{-}\text{C}^{+}\text{H}_{2}\) (III)
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More alkyl groups give more +I effect and more hyperconjugation, so stability increases.
Updated On: Nov 12, 2026
- III > II > I
- II > I > III
- I > III > II
- I > II > III
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
Alkyl groups stabilise a carbocation by the +I effect and hyperconjugation.
Step 2: Count
I is tertiary with 9 alpha hydrogens.
II is secondary with 6 alpha hydrogens.
III is primary with 3 alpha hydrogens.
Step 3: Conclusion
More hyperconjugation means more stability, so I > II > III.
Final Answer:
The stability order is I > II > III. \[ \boxed{\text{(D) }\text{I}>\text{II}>\text{III}} \]
Alkyl groups stabilise a carbocation by the +I effect and hyperconjugation.
Step 2: Count
I is tertiary with 9 alpha hydrogens.
II is secondary with 6 alpha hydrogens.
III is primary with 3 alpha hydrogens.
Step 3: Conclusion
More hyperconjugation means more stability, so I > II > III.
Final Answer:
The stability order is I > II > III. \[ \boxed{\text{(D) }\text{I}>\text{II}>\text{III}} \]
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