Question:

Choose the transition element which exhibit least number of variable oxidation states.

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Scandium predominantly shows only \(+3\) oxidation state, whereas manganese exhibits the maximum number of oxidation states in the first transition series.
Updated On: Jun 11, 2026
  • \(\mathrm{Sc}\)
  • \(\mathrm{Cr}\)
  • \(\mathrm{Mn}\)
  • \(\mathrm{Fe}\)
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The Correct Option is A

Solution and Explanation

Concept: Variable oxidation states arise due to the small energy difference between \((n-1)d\) and \(ns\) orbitals in transition elements. The greater the number of available electrons, the larger the number of oxidation states possible.

Step 1:
Consider scandium.
Electronic configuration: \[ Sc=[Ar]\,3d^1 4s^2 \] The most stable oxidation state is \[ +3 \] Scandium rarely exhibits other oxidation states. Therefore it has the least variability.

Step 2:
Consider chromium.
Chromium exhibits \[ +2,\ +3,\ +6 \] and several intermediate oxidation states.

Step 3:
Consider manganese.
Manganese shows the largest range of oxidation states. \[ +2 \text{ to } +7 \]

Step 4:
Consider iron.
Iron commonly exhibits \[ +2,\ +3 \] and a few additional oxidation states.

Step 5:
Select the element showing minimum variability.
Among all the given elements, scandium exhibits the least number of oxidation states. \[ \boxed{\mathrm{Sc}} \]
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