Step 1: Understanding the Concept:
Brewster law says that reflected light is fully polarised when \(\tan i_p = \mu\), where \(\mu\) is the refractive index of the medium.
Step 2: Detailed Explanation:
The refractive index changes with wavelength, so \(\mu\) is different for different colours. So \(i_p = \tan^{-1}\mu\) is different for different colours.
Step 3: Check the options.
(B) says the same for all colours, which is wrong. (C) says it does not depend on refractive index, which is the opposite of the law. (D) says it differs for light of the same colour, which is wrong because the same colour has one wavelength and one index.
Final Answer:
Brewster's angle differs for different colours, option (A).
\[ \boxed{\text{(A)}} \]