Choose the correct and major product formed in the below-given reaction from the choices listed below:
- 3-Pentene
- 2-Methyl-2-butene
- 1-Pentane
- 1-Methyl-2-butene
The Correct Option is B
Solution and Explanation
In the given reaction, we need to determine the major product formed from a β-elimination (dehydrohalogenation) reaction, which typically follows the E2 mechanism.
The given compound is 2-Bromo-3-methylbutane. When reacted with ethanol (EtOH), a protic solvent, the elimination reaction results in the removal of the halogen (Br) and a hydrogen atom from the adjacent carbon atom, forming a double bond.
Applying Zaitsev's rule, which states that the more substituted alkene will be favored as the major product, we look for the formation of a double bond with greater substitution:
The possible alkenes are:
- 3-Pentene - Less substituted alkene.
- 2-Methyl-2-butene - More substituted alkene.
- 1-Pentene - Least substituted alkene.
- 1-Methyl-2-butene - Less substituted compared to 2-methyl-2-butene.
Thus, according to Zaitsev's rule, 2-Methyl-2-butene will be the major product as it is the more substituted alkene.
The reaction can be represented as follows:
\(\text{2-Bromo-3-methylbutane} \xrightarrow{\text{EtOH}} 2-\text{Methyl-2-butene} + \text{HBr}\)
Therefore, the correct answer is 2-Methyl-2-butene.
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