Question:
Chlorination of alkane is a photochemical process. It is initiated by the process of
Chlorination of alkane is a photochemical process. It is initiated by the process of
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The initiation step splits the Cl-Cl bond evenly to give free radicals.
Updated On: Nov 12, 2026
- heterolysis
- homolysis
- pyrolysis
- hydrolysis
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Chlorination of an alkane in light is a free-radical chain reaction.
Step 2: Initiation step
UV light splits the \(\text{Cl--Cl}\) bond evenly, with each atom keeping one bonding electron: \(\text{Cl}_{2}\rightarrow 2\text{Cl}\cdot\).
Step 3: Result
Symmetrical bond fission that gives free radicals is called homolysis. Heterolysis would give ions.
Final Answer:
The reaction is initiated by homolysis. \[ \boxed{\text{(B) }\text{homolysis}} \]
Chlorination of an alkane in light is a free-radical chain reaction.
Step 2: Initiation step
UV light splits the \(\text{Cl--Cl}\) bond evenly, with each atom keeping one bonding electron: \(\text{Cl}_{2}\rightarrow 2\text{Cl}\cdot\).
Step 3: Result
Symmetrical bond fission that gives free radicals is called homolysis. Heterolysis would give ions.
Final Answer:
The reaction is initiated by homolysis. \[ \boxed{\text{(B) }\text{homolysis}} \]
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