Question:
$CH _{3} COOH \xrightarrow{ LiAlH _{4}}A + CH _{3} COOH \xrightarrow{ H _{3} O ^{+}} B + H _{2} O$
In the above reactions ' $A$ ' and ' $B$ ' respectively are
$CH _{3} COOH \xrightarrow{ LiAlH _{4}}A + CH _{3} COOH \xrightarrow{ H _{3} O ^{+}} B + H _{2} O$
In the above reactions ' $A$ ' and ' $B$ ' respectively are
Updated On: Jul 27, 2022
- $CH_{3}COOC_{2} H_{5},\, C_{2}H_{5}OH$
- $CH_{3}CHO,\,C_{2} H_{5} OH$
- $C_{2}H_{5}OH,\,CH_{3} CHO$
- $C_{2}H_{5}OH,\,CH_{3}COOC_{2} H_{5}$
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The Correct Option is D
Solution and Explanation
$CH _{3} COOH +4 H \xrightarrow{\text { LiAlH }_{4}}\underset{(A)}{CH _{3} CH _{2} OH} + H _{2} O$
$\underset{(A)}{CH _{3} CH _{2} OH} + CH _{3} COOH \stackrel{ H _{3} O ^{+}}{\longrightarrow}$
$\underset{(B)}{C{H}_{3}COOC_{2} H_{5}}+H_{2}O$
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