Step 1: Recall formula for capacitive reactance.
\[
X_C = \frac{1}{2 \pi f C}
\]
Step 2: Identify given values.
Initial reactance: \(X_{C1} = 6 \, \text{k}\Omega\), frequency \(f_1\). New frequency \(f_2 = 2 f_1\).
Step 3: Determine new reactance.
\[
X_{C2} = \frac{1}{2 \pi f_2 C} = \frac{1}{2 \pi (2 f_1) C} = \frac{X_{C1}}{2}
\]
Step 4: Substitute values.
\[
X_{C2} = \frac{6}{2} = 3 \, \text{k}\Omega
\]
Step 5: Verify reasoning.
Doubling frequency halves the capacitive reactance; formula consistent.
Step 6: Final conclusion.
Hence, the capacitive reactance at double frequency is:
\[
\boxed{3 \, \text{k}\Omega}
\]