Question:
Calculate the work done in moving a charge of \(2\mu C\) between two points with a potential difference of \(5V\).
Calculate the work done in moving a charge of \(2\mu C\) between two points with a potential difference of \(5V\).
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In electrostatics problems involving potential difference, always use
\(W = q\Delta V\). Convert microcoulombs (\(\mu C\)) into coulombs before substitution.
Updated On: May 3, 2026
- \(10\,J\)
- \(10^{-5}\,J\)
- \(2.5\,J\)
- \(0.4\,J\)
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The Correct Option is B
Solution and Explanation
Concept:
The work done in moving a charge in an electric field is given by:
\[
W = q \times \Delta V
\]
where
\(W\) = work done,
\(q\) = charge,
\(\Delta V\) = potential difference.
Step 1: Substitute the given values. \[ q = 2\mu C = 2 \times 10^{-6} C \] \[ \Delta V = 5V \] \[ W = q \times \Delta V \]
Step 2: Calculate the work done. \[ W = (2 \times 10^{-6}) \times 5 \] \[ W = 10 \times 10^{-6} \] \[ W = 10^{-5} J \]
Step 1: Substitute the given values. \[ q = 2\mu C = 2 \times 10^{-6} C \] \[ \Delta V = 5V \] \[ W = q \times \Delta V \]
Step 2: Calculate the work done. \[ W = (2 \times 10^{-6}) \times 5 \] \[ W = 10 \times 10^{-6} \] \[ W = 10^{-5} J \]
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