Question:
Calculate the volume of \(99\) g of \(\text{CO}_2\) at STP ?
Calculate the volume of \(99\) g of \(\text{CO}_2\) at STP ?
Show Hint
Find the moles of CO2 from the mass, then multiply by 22.4 L, the molar volume at STP.
Updated On: Oct 1, 2026
- \(22.4\) L
- \(50.4\) L
- \(67.2\) L
- \(89.6\) L
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
One mole of any ideal gas occupies 22.4 L at STP. So we first convert the given mass into moles, then convert moles into volume.
Step 2: Key Formula or Approach:
\(n = \dfrac{\text{mass}}{\text{molar mass}}\) and \(V_{\text{STP}} = n \times 22.4\) L.
Step 3: Find the molar mass of CO2:
\(M(\text{CO}_2) = 12 + 2(16) = 44\) g/mol.
Step 4: Find the number of moles:
\(n = \dfrac{99}{44} = 2.25\) mol.
Step 5: Find the volume:
\(V = 2.25 \times 22.4 = 50.4\) L.
Step 6: Why the other options are wrong.
22.4 L is the volume of just 1 mole (44 g). 67.2 L is the volume of 3 moles (132 g). 89.6 L is the volume of 4 moles (176 g). None of these match 99 g.
Final Answer:
The volume of 99 g of CO2 at STP is \(50.4\) L. \[ \boxed{\text{(B) }50.4\ \text{L}} \]
One mole of any ideal gas occupies 22.4 L at STP. So we first convert the given mass into moles, then convert moles into volume.
Step 2: Key Formula or Approach:
\(n = \dfrac{\text{mass}}{\text{molar mass}}\) and \(V_{\text{STP}} = n \times 22.4\) L.
Step 3: Find the molar mass of CO2:
\(M(\text{CO}_2) = 12 + 2(16) = 44\) g/mol.
Step 4: Find the number of moles:
\(n = \dfrac{99}{44} = 2.25\) mol.
Step 5: Find the volume:
\(V = 2.25 \times 22.4 = 50.4\) L.
Step 6: Why the other options are wrong.
22.4 L is the volume of just 1 mole (44 g). 67.2 L is the volume of 3 moles (132 g). 89.6 L is the volume of 4 moles (176 g). None of these match 99 g.
Final Answer:
The volume of 99 g of CO2 at STP is \(50.4\) L. \[ \boxed{\text{(B) }50.4\ \text{L}} \]
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