Question:
Calculate the volume occupied by \(64\text{ g}\) dioxygen at STP.
Calculate the volume occupied by \(64\text{ g}\) dioxygen at STP.
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Convert the mass to moles using the molar mass and multiply by the molar volume at STP.
Updated On: Nov 12, 2026
- \(22.4\text{ L}\)
- \(44.8\text{ L}\)
- \(11.2\text{ L}\)
- \(33.6\text{ L}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
One mole of any ideal gas occupies 22.4 L at STP.
Step 2: Moles
Molar mass of \(\text{O}_2\) is \(32\text{ g mol}^{-1}\).
\(n = \dfrac{64}{32} = 2\text{ mol}\)
Step 3: Volume
\(V = 2 \times 22.4 = 44.8\text{ L}\)
Final Answer:
64 g of dioxygen occupies 44.8 L at STP. \[ \boxed{\text{(B) }44.8\text{ L}} \]
One mole of any ideal gas occupies 22.4 L at STP.
Step 2: Moles
Molar mass of \(\text{O}_2\) is \(32\text{ g mol}^{-1}\).
\(n = \dfrac{64}{32} = 2\text{ mol}\)
Step 3: Volume
\(V = 2 \times 22.4 = 44.8\text{ L}\)
Final Answer:
64 g of dioxygen occupies 44.8 L at STP. \[ \boxed{\text{(B) }44.8\text{ L}} \]
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