Question:
Ca\(^{2+}\) + Na\(_6\)(PO\(_3\))\(_6\) → X + yNa\(^+\). Identify X
Ca\(^{2+}\) + Na\(_6\)(PO\(_3\))\(_6\) → X + yNa\(^+\). Identify X
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In complex salts, multivalent ions like \(Ca^{2+}\) often replace two monovalent ions like \(Na^+\).
Updated On: Jun 19, 2026
- \([Na_2Ca(PO_3)_6]^{2-}\)
- \([Ca_2(PO_3)_6]^{2-}\)
- \([Na_4Ca(PO_3)_6]\)
- \([Ca_3(PO_3)_6]\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the nature of compound.
The compound \(Na_6(PO_3)_6\) is a complex salt where sodium ions balance the negative charge of the polyphosphate unit \((PO_3)_6\).
Step 2: Role of calcium ion.
When \(Ca^{2+}\) is added, it replaces some of the sodium ions due to its higher charge density and ability to form more stable coordination complexes.
Step 3: Charge balance consideration.
Initially, \((PO_3)_6\) has a high negative charge balanced by 6 \(Na^+\). When \(Ca^{2+}\) enters, it replaces two sodium ions because: \[ Ca^{2+} \equiv 2Na^+ \]
Step 4: Formation of mixed salt.
Thus, part of sodium remains and calcium coordinates with the phosphate chain, forming a mixed complex: \[ [Na_2Ca(PO_3)_6]^{2-} \]
Step 5: Final verification.
The remaining sodium ions appear as \(yNa^+\), confirming partial substitution and correct charge balance in the complex ion.
Final Answer: \[ \boxed{[Na_2Ca(PO_3)_6]^{2-}} \]
The compound \(Na_6(PO_3)_6\) is a complex salt where sodium ions balance the negative charge of the polyphosphate unit \((PO_3)_6\).
Step 2: Role of calcium ion.
When \(Ca^{2+}\) is added, it replaces some of the sodium ions due to its higher charge density and ability to form more stable coordination complexes.
Step 3: Charge balance consideration.
Initially, \((PO_3)_6\) has a high negative charge balanced by 6 \(Na^+\). When \(Ca^{2+}\) enters, it replaces two sodium ions because: \[ Ca^{2+} \equiv 2Na^+ \]
Step 4: Formation of mixed salt.
Thus, part of sodium remains and calcium coordinates with the phosphate chain, forming a mixed complex: \[ [Na_2Ca(PO_3)_6]^{2-} \]
Step 5: Final verification.
The remaining sodium ions appear as \(yNa^+\), confirming partial substitution and correct charge balance in the complex ion.
Final Answer: \[ \boxed{[Na_2Ca(PO_3)_6]^{2-}} \]
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