Question:
Borax dissolves in water and forms a product of boron \((X)\). Identify the compound \(X\).
Borax dissolves in water and forms a product of boron \((X)\). Identify the compound \(X\).
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Borax hydrolyses in water to form boric acid \((H_3BO_3)\), which is a weak monobasic Lewis acid.
Updated On: Jun 25, 2026
- \(HBO_2\)
- \(B_2O_3\)
- \(NaBO_2\)
- \(H_3BO_3\)
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The Correct Option is D
Solution and Explanation
Step 1: Understand borax hydrolysis.
Borax is: \[ Na_2B_4O_7\cdot10H_2O \] When dissolved in water, borax undergoes hydrolysis.
Step 2: Write the reaction.
\[ Na_2B_4O_7+7H_2O\rightarrow 2NaOH+4H_3BO_3 \] Thus, boric acid is formed.
Step 3: Identify compound \(X\).
The boron compound produced is: \[ H_3BO_3 \]
Step 4: Final conclusion.
Hence, \[ \boxed{H_3BO_3} \] is compound \(X\).
Borax is: \[ Na_2B_4O_7\cdot10H_2O \] When dissolved in water, borax undergoes hydrolysis.
Step 2: Write the reaction.
\[ Na_2B_4O_7+7H_2O\rightarrow 2NaOH+4H_3BO_3 \] Thus, boric acid is formed.
Step 3: Identify compound \(X\).
The boron compound produced is: \[ H_3BO_3 \]
Step 4: Final conclusion.
Hence, \[ \boxed{H_3BO_3} \] is compound \(X\).
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