Question:
Boolean relation at the output stage-Y for the following circuit is :
Boolean relation at the output stage-Y for the following circuit is :
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Two parallel diodes with switches form an OR stage; the transistor in common-emitter mode inverts it.
Updated On: Nov 5, 2026
- \(A \cdot B\)
- \(\overline{A} + \overline{B}\)
- \(\overline{A} \cdot \overline{B}\)
- \(A + B\)
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The Correct Option is C
Solution and Explanation
Each switch (A, B) connects the 5 V supply to the base network through a diode; the two diodes are in parallel. If either switch is closed (input 1) the common point goes high, so this stage gives \(A + B\) (OR gate).
This signal drives the base of a transistor used in common-emitter configuration. When the base is high the transistor saturates and the collector (output Y) is pulled to ground (0); when the base is low the transistor is off and Y is high (a NOT gate).
\(Y = \overline{A + B} = \overline{A}\cdot\overline{B}\) (NOR gate).
Answer: (3) \(\overline{A}\cdot\overline{B}\)
This signal drives the base of a transistor used in common-emitter configuration. When the base is high the transistor saturates and the collector (output Y) is pulled to ground (0); when the base is low the transistor is off and Y is high (a NOT gate).
\(Y = \overline{A + B} = \overline{A}\cdot\overline{B}\) (NOR gate).
Answer: (3) \(\overline{A}\cdot\overline{B}\)
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