Question:

Binary stars \(m_A, m_B\) move in circular orbits. Compare their time periods.

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Binary system $\Rightarrow$ same angular velocity $\Rightarrow$ same time period.
Updated On: Apr 23, 2026
  • \(\frac{T_A}{T_B} = \left(\frac{r_A}{r_B}\right)^{3/2}\)
  • \(T_A>T_B\) if \(r_A>r_B\)
  • \(T_A>T_B\) if \(m_A>m_B\)
  • \(T_A = T_B\)
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The Correct Option is D

Solution and Explanation

Concept: Binary stars revolve about common centre of mass. \[ T = 2\pi\sqrt{\frac{r^3}{G(m_A + m_B)}} \]

Step 1:
Same system
Both stars share same angular velocity. \[ \omega_A = \omega_B \Rightarrow T_A = T_B \] Conclusion: \[ T_A = T_B \]
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