Question:

At T (K), the molarity of 34% (w/w) NH$_3$ solution (density 0.9 g mL$^{-1}$) is:

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Updated On: Jul 18, 2026
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The Correct Option is D

Solution and Explanation

Step 1: Assume 100 g of solution.
For 34% (w/w) solution: \[ \text{NH}_3 = 34\,g,\quad \text{water} = 66\,g \]

Step 2: Convert mass of solution to volume.
Density = 0.9 g/mL: \[ \text{Volume} = \frac{100}{0.9} \approx 111.11 \, mL = 0.1111 \, L \]

Step 3: Calculate moles of NH$_3$.
Molar mass of NH$_3$ = 17 g/mol: \[ n = \frac{34}{17} = 2 \, mol \]

Step 4: Calculate molarity.
\[ M = \frac{2}{0.1111} \approx 18 \]

Step 5: Final conclusion.
\[ \boxed{18} \]
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