Question:
At $T$ (K), a gas obeys kinetic gas equation. At this temperature, for a given number of molecules, PV = x. If the number of molecules is doubled at $T$, then the value of PV would be
At $T$ (K), a gas obeys kinetic gas equation. At this temperature, for a given number of molecules, PV = x. If the number of molecules is doubled at $T$, then the value of PV would be
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In $PV = nRT$, if $T$ is constant and $n$ is doubled, $PV$ also doubles.
Updated On: May 12, 2025
- $x$
- $x^2$
- $4x$
- $2x$
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The Correct Option is D
Solution and Explanation
From the ideal gas law: $PV = nRT$
If temperature $T$ is constant and $n$ is the number of moles (proportional to number of molecules), then doubling the number of molecules doubles $n$
So, $PV \propto n \Rightarrow PV$ becomes $2x$
If temperature $T$ is constant and $n$ is the number of moles (proportional to number of molecules), then doubling the number of molecules doubles $n$
So, $PV \propto n \Rightarrow PV$ becomes $2x$
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