Question:
Assertion (A): Finely divided charcoal can act as an adsorbent.
Reason (R): Finely divided material has small surface area.
Assertion (A): Finely divided charcoal can act as an adsorbent.
Reason (R): Finely divided material has small surface area.
Reason (R): Finely divided material has small surface area.
Show Hint
Adsorption is a surface phenomenon. Greater the surface area of the adsorbent, greater is its adsorption capacity. Finely divided solids such as activated charcoal are excellent adsorbents because of their very large surface area.
Updated On: Jun 26, 2026
- Both (A) and (R) are correct and (R) is the correct explanation of (A).
- Both (A) and (R) are correct but (R) is not the correct explanation of (A).
- (A) is correct but (R) is incorrect.
- (A) is incorrect but (R) is correct.
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Analyze Assertion (A).
Finely divided charcoal is a well-known adsorbent.
Adsorption is a surface phenomenon in which molecules of a gas or solute accumulate on the surface of a solid.
Charcoal possesses a highly porous structure and a very large surface area. Therefore, it can adsorb large quantities of gases and dissolved substances.
Hence, Assertion (A) is correct.
Step 2: Analyze Reason (R).
The reason states that finely divided material has small surface area.
This statement is incorrect.
When a substance is finely divided, its surface area increases significantly because the same mass is broken into a large number of smaller particles.
Therefore, Finely divided material has large surface area, not small surface area. Hence, Reason (R) is incorrect.
Step 3: Relate adsorption with surface area.
Adsorption increases with increase in surface area.
Since finely divided charcoal has a very large surface area, it acts as an effective adsorbent.
Thus, the assertion is true, but the reason is false.
Step 4: Final conclusion.
Therefore, \[ \boxed{\text{(A) is correct but (R) is incorrect}} \] Hence, the correct option is \[ \boxed{(3)} \]
Finely divided charcoal is a well-known adsorbent.
Adsorption is a surface phenomenon in which molecules of a gas or solute accumulate on the surface of a solid.
Charcoal possesses a highly porous structure and a very large surface area. Therefore, it can adsorb large quantities of gases and dissolved substances.
Hence, Assertion (A) is correct.
Step 2: Analyze Reason (R).
The reason states that finely divided material has small surface area.
This statement is incorrect.
When a substance is finely divided, its surface area increases significantly because the same mass is broken into a large number of smaller particles.
Therefore, Finely divided material has large surface area, not small surface area. Hence, Reason (R) is incorrect.
Step 3: Relate adsorption with surface area.
Adsorption increases with increase in surface area.
Since finely divided charcoal has a very large surface area, it acts as an effective adsorbent.
Thus, the assertion is true, but the reason is false.
Step 4: Final conclusion.
Therefore, \[ \boxed{\text{(A) is correct but (R) is incorrect}} \] Hence, the correct option is \[ \boxed{(3)} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET General Chemistry Questions
- Observe the following given changes: \[ \text{wood} \xrightarrow[\text{absence of air}]{\text{high temperature}} X
\text{coal} \xrightarrow[\text{absence of air}]{\text{high temperature}} Y \] X and Y respectively are: - Calculate the amount of \( CO_2 \) gas produced, when \( 32 \)g of \( CH_4 \) is burned with sufficient amount of oxygen (Given atomic weight of \( C=12, O=16 \) and \( H=1 \))
- The conjugate acid of $NH_2^-$ is:
- Which one of the pairs will form a buffer solution?
- The greater the valence of the flocculating ion added, the greater is its power to cause precipitation of a colloid. This rule is:
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions