Concept:
The Fermi level position in semiconductors depends on doping.
Step 1: \(p\)-type semiconductor.
In a \(p\)-type semiconductor, the Fermi level lies closer to the valence band.
So, its distance from the valence band is smallest.
\[
A \text{ is lowest}
\]
Step 2: Intrinsic semiconductor.
In an intrinsic semiconductor, the Fermi level lies near the middle of the band gap.
\[
C \text{ is above } A
\]
Step 3: \(n\)-type semiconductor.
In an \(n\)-type semiconductor, the Fermi level lies closer to the conduction band.
\[
B \text{ is above } C
\]
Step 4: \(n\)-type degenerate semiconductor.
In a degenerate \(n\)-type semiconductor, the Fermi level may enter the conduction band.
So, it has the highest Fermi level from the valence band.
\[
D \text{ is highest}
\]
Therefore, decreasing order is:
\[
D>B>C>A
\]
\[
\therefore \text{Correct Answer is (C)}
\]