Question:
Arrange the following species in the decreasing order of their bond orders:
Arrange the following species in the decreasing order of their bond orders:
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For diatomic species, calculate bond order using molecular orbital theory to compare bond strengths.
Updated On: Jun 26, 2026
- NO > NO+ > NO−
- NO+ > NO > NO−
- NO+ > NO− > NO
- NO− > NO > NO+
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The Correct Option is B
Solution and Explanation
Step 1: Recall bond order formula.
Bond order is calculated as \[ \text{Bond order} = \frac{(\text{number of bonding electrons}) - (\text{number of antibonding electrons})}{2}. \]
Step 2: Determine bond orders.
- NO has bond order 2.5
- NO+ has bond order 3
- NO− has bond order 2
Step 3: Arrange in decreasing order.
\[ \text{Decreasing bond order: } NO+ \gt NO \gt NO− \]
Step 4: Conclusion.
Hence, the correct decreasing order is \[ \boxed{NO+ \gt NO \gt NO−}. \]
Bond order is calculated as \[ \text{Bond order} = \frac{(\text{number of bonding electrons}) - (\text{number of antibonding electrons})}{2}. \]
Step 2: Determine bond orders.
- NO has bond order 2.5
- NO+ has bond order 3
- NO− has bond order 2
Step 3: Arrange in decreasing order.
\[ \text{Decreasing bond order: } NO+ \gt NO \gt NO− \]
Step 4: Conclusion.
Hence, the correct decreasing order is \[ \boxed{NO+ \gt NO \gt NO−}. \]
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