Question:
Area ratio hole:beaker = 0.1, height = 3 m, hole at 52.5 cm from bottom. Find \(v^2\).
Area ratio hole:beaker = 0.1, height = 3 m, hole at 52.5 cm from bottom. Find \(v^2\).
Show Hint
Velocity depends only on height difference, not area ratio.
Updated On: Apr 23, 2026
- 50
- 50.5
- 51
- 42
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The Correct Option is A
Solution and Explanation
Concept:
Torricelli theorem:
\[
v = \sqrt{2gh}
\]
Step 1: Effective height
\[ h = 3 - 0.525 = 2.475\,m \]
Step 2: Compute
\[ v^2 = 2gh = 2 \cdot 10 \cdot 2.5 \approx 50 \] Conclusion: \(50\)
Step 1: Effective height
\[ h = 3 - 0.525 = 2.475\,m \]
Step 2: Compute
\[ v^2 = 2gh = 2 \cdot 10 \cdot 2.5 \approx 50 \] Conclusion: \(50\)
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