Question:
An unpolarised light of intensity \(64\text{ Wm}^{-2}\) passes through three polarizers successively such that the transmission axis of last polarizer is crossed with the first. The intensity of the emerging light is \(6\text{ Wm}^{-2}\). The angle between the transmission axis of the first two polarizers is
An unpolarised light of intensity \(64\text{ Wm}^{-2}\) passes through three polarizers successively such that the transmission axis of last polarizer is crossed with the first. The intensity of the emerging light is \(6\text{ Wm}^{-2}\). The angle between the transmission axis of the first two polarizers is
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The refractive index depends on wavelength, so different colours bend by different amounts.
Updated On: Oct 1, 2026
- \(\frac{1}{2}sin^{-1}(\frac{\sqrt{3}}{2})\)
- \(\frac{1}{2}cos^{-1}(\frac{\sqrt{3}}{2})\)
- \(\frac{1}{2}sin^{-1}(\frac{1}{\sqrt{3}})\)
- \(\frac{1}{2}cos^{-1}(\frac{1}{\sqrt{3}})\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
By Snell's law, \(\sin i = n\sin r\). The refractive index n of a medium depends on the wavelength (colour) of light.
Step 2: Result:
For the same angle of incidence, different colours have different n, and therefore different angles of refraction. Violet bends the most and red the least. This is the cause of dispersion.
So (B) is true, while (A) and (C) say the opposite. The critical angle in (D) is a separate idea for total internal reflection and does not decide the angle of refraction.
Final Answer:
The angle of refraction differs for different colours, option (B). \[ \boxed{\text{(B)}} \]
By Snell's law, \(\sin i = n\sin r\). The refractive index n of a medium depends on the wavelength (colour) of light.
Step 2: Result:
For the same angle of incidence, different colours have different n, and therefore different angles of refraction. Violet bends the most and red the least. This is the cause of dispersion.
So (B) is true, while (A) and (C) say the opposite. The critical angle in (D) is a separate idea for total internal reflection and does not decide the angle of refraction.
Final Answer:
The angle of refraction differs for different colours, option (B). \[ \boxed{\text{(B)}} \]
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