Question:
An organic compound contains 90% carbon and 10% hydrogen by mass. Its empirical formula is
An organic compound contains 90% carbon and 10% hydrogen by mass. Its empirical formula is
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Always:
Mass → moles → divide by smallest → whole number ratio.
Updated On: May 8, 2026
- C$_2$H$_4$
- C$_3$H$_6$
- C$_3$H$_8$
- C$_3$H$_4$
- C$_2$H$_6$
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The Correct Option is D
Solution and Explanation
Concept:
Empirical formula = simplest whole number ratio of atoms.
Step 1: Assume 100 g compound \[ \text{C} = 90g,\quad \text{H} = 10g \]
Step 2: Convert to moles \[ \text{Moles of C} = \frac{90}{12} = 7.5 \] \[ \text{Moles of H} = \frac{10}{1} = 10 \]
Step 3: Simplify ratio \[ C : H = 7.5 : 10 \] Divide by 2.5: \[ C : H = 3 : 4 \]
Step 4: Empirical formula \[ \boxed{C_3H_4} \]
Step 1: Assume 100 g compound \[ \text{C} = 90g,\quad \text{H} = 10g \]
Step 2: Convert to moles \[ \text{Moles of C} = \frac{90}{12} = 7.5 \] \[ \text{Moles of H} = \frac{10}{1} = 10 \]
Step 3: Simplify ratio \[ C : H = 7.5 : 10 \] Divide by 2.5: \[ C : H = 3 : 4 \]
Step 4: Empirical formula \[ \boxed{C_3H_4} \]
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