An open tank filled with water (density $\rho$) has a narrow hole at a depth of $h$ below the water surface. The velocity of water flowing out is
Show Hint
- $h\rho g$
- $2gh$
- $\sqrt{2gh}$
- $\sqrt{2h\rho g}$
The Correct Option is C
Solution and Explanation
Torricelli's law gives the speed of efflux.
Step 2: Detailed Explanation:
Applying Bernoulli's theorem at the water surface and at the hole: $P_{atm} + \rho g h + 0 = P_{atm} + \frac{1}{2}\rho v^2 + 0$. Solving gives $v = \sqrt{2gh}$.
Step 3: Final Answer:
The velocity is $\sqrt{2gh}$.
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