Question:
An isomer of \(\mathrm{C_4H_8}\) is \(X\), which exhibits cis-trans isomerism. \(Y\) is the chain isomer of \(X\). Products formed on ozonolysis of \(Y\) are
An isomer of \(\mathrm{C_4H_8}\) is \(X\), which exhibits cis-trans isomerism. \(Y\) is the chain isomer of \(X\). Products formed on ozonolysis of \(Y\) are
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Ozonolysis cleaves the C=C bond to form carbonyl compounds.
- Terminal carbon (\(\mathrm{=CH_2}\)) gives formaldehyde (\(\mathrm{HCHO}\)).
- Internal substituted carbon generally gives an aldehyde or ketone.
Updated On: Jul 9, 2026
- \(\mathrm{CH_3CHO + CH_3CHO}\)
- \(\mathrm{CH_3CH_2CHO + HCOOH}\)
- \(\mathrm{CH_3COCH_3 + HCHO}\)
- \(\mathrm{CH_3CH_2COOH + CO_2}\) \bigskip
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The Correct Option is C
Solution and Explanation
Step 1: Identify \(X\).
Among the isomers of \(\mathrm{C_4H_8}\), only but-2-ene exhibits cis-trans isomerism.
\[
X=\mathrm{CH_3CH=CHCH_3}
\]
Step 2: Identify the chain isomer \(Y\). The chain isomer of but-2-ene is \[ Y=\mathrm{(CH_3)_2C=CH_2} \] (2-methylpropene).
Step 3: Apply ozonolysis. \[ \mathrm{(CH_3)_2C=CH_2} \xrightarrow[\mathrm{Zn/H_2O}]{\mathrm{O_3}} \mathrm{CH_3COCH_3 + HCHO} \]
Step 4: Final conclusion. Hence, the products formed are \[ \boxed{\mathrm{CH_3COCH_3 + HCHO}} \] Therefore, the correct option is \(\boxed{(C)}\).
Step 2: Identify the chain isomer \(Y\). The chain isomer of but-2-ene is \[ Y=\mathrm{(CH_3)_2C=CH_2} \] (2-methylpropene).
Step 3: Apply ozonolysis. \[ \mathrm{(CH_3)_2C=CH_2} \xrightarrow[\mathrm{Zn/H_2O}]{\mathrm{O_3}} \mathrm{CH_3COCH_3 + HCHO} \]
Step 4: Final conclusion. Hence, the products formed are \[ \boxed{\mathrm{CH_3COCH_3 + HCHO}} \] Therefore, the correct option is \(\boxed{(C)}\).
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