An inclined plane makes an angle 30° with horizontal. A solid sphere rolling down this inclined plane has a linear acceleration of
Show Hint
- \(\frac{5g}{14}\)
- \(\frac{2g}{3}\)
- \(\frac{g}{3}\)
- \(\frac{5g}{7}\)
The Correct Option is A
Solution and Explanation
For rolling: \(a = \frac{g\sin\theta}{1 + k^2/r^2}\).
Step 2: Detailed Explanation:
For solid sphere, \(k^2/r^2 = 2/5\)
\(a = \frac{g\sin 30^\circ}{1 + 2/5} = \frac{g/2}{7/5} = \frac{g}{2} \times \frac{5}{7} = \frac{5g}{14}\)
Step 3: Final Answer:
Acceleration is \(\frac{5g}{14}\).
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