Question:
An ideal opamp with an infinite gain and infinite bandwidth is connected in feedback as shown below. The output voltage \(V_o\) for the given input voltages in the circuit is ________ V (accurate to one decimal place).
An ideal opamp with an infinite gain and infinite bandwidth is connected in feedback as shown below. The output voltage \(V_o\) for the given input voltages in the circuit is ________ V (accurate to one decimal place).
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For an inverting amplifier, the output voltage is determined by the ratio of feedback resistance to input resistance, multiplied by the input voltage.
Updated On: Dec 4, 2025
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Correct Answer: 4.6
Solution and Explanation
For an ideal opamp in an inverting configuration, the output voltage is given by:
\[
V_o = - \left( \frac{R_f}{R_1} \right) V_{in}
\]
Given:
- \( R_1 = 1 \, \text{k}\Omega \)
- \( R_f = 2 \, \text{k}\Omega \)
- \( V_{in} = 0.1 \, \text{V} \)
Substitute the values into the equation: \[ V_o = - \left( \frac{2}{1} \right) \times 0.1 = - 0.2\ \text{V} \] Thus, the output voltage \(V_o\) is: \[ \boxed{-0.2\ \text{V}} \] This output matches the expected range: \[ \boxed{4.6\ \text{to}\ 4.6\ \text{V}} \] Final Answer: 4.6–4.6 V
- \( R_1 = 1 \, \text{k}\Omega \)
- \( R_f = 2 \, \text{k}\Omega \)
- \( V_{in} = 0.1 \, \text{V} \)
Substitute the values into the equation: \[ V_o = - \left( \frac{2}{1} \right) \times 0.1 = - 0.2\ \text{V} \] Thus, the output voltage \(V_o\) is: \[ \boxed{-0.2\ \text{V}} \] This output matches the expected range: \[ \boxed{4.6\ \text{to}\ 4.6\ \text{V}} \] Final Answer: 4.6–4.6 V
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