Step 1: Use the work done formula for a constant pressure process.
For an isobaric process,
\[
W=P\Delta V
\]
Using the ideal gas equation,
\[
PV=nRT
\]
At constant pressure,
\[
P\Delta V=nR\Delta T
\]
Therefore,
\[
W=nR\Delta T
\]
Step 2: Calculate the change in temperature.
Initial temperature,
\[
T_1=30^\circ\text{C}
\]
Final temperature,
\[
T_2=130^\circ\text{C}
\]
Hence,
\[
\Delta T=T_2-T_1
\]
\[
\Delta T=130-30
\]
\[
\Delta T=100\,\text{K}
\]
Step 3: Substitute the given values.
Given,
\[
n=1.5
\]
\[
R=8.3\,\text{J mol}^{-1}\text{K}^{-1}
\]
\[
\Delta T=100\,\text{K}
\]
Therefore,
\[
W=nR\Delta T
\]
\[
W=1.5\times 8.3\times 100
\]
\[
W=1245\,\text{J}
\]
Step 4: Final conclusion.
Hence, the work done by the gas is
\[
\boxed{1245\,\text{J}}
\]