Question:

An ideal gas expands along the path AB as shown in the p-V diagram. The work done is

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An ideal gas expands along the path AB as shown in the p-V diagram. The work done is
Updated On: Apr 15, 2026
  • $4 \times 10^4$ J
  • $1.2 \times 10^5$ J
  • $2.4 \times 10^5$ J
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: Concept
Work done is equal to the area under the p-V curve.
Step 2: Analysis
The area is a trapezium: $\text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times (\text{distance between them})$.
Step 3: Calculation
$W = \frac{1}{2} \times (8 + 4) \times 10^5 \text{ Pa} \times (0.5 - 0.3) \text{ m}^3$ $W = \frac{1}{2} \times 12 \times 10^5 \times 0.2 = 1.2 \times 10^5 \text{ J}$.
Final Answer: (B)
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