Question:
An element \(X\) with atomic number \(13\) forms a complex of the type \([XCl(H_2O)_5]^{2+}\). The covalency and oxidation state of \(X\) in it are respectively
An element \(X\) with atomic number \(13\) forms a complex of the type \([XCl(H_2O)_5]^{2+}\). The covalency and oxidation state of \(X\) in it are respectively
Show Hint
In coordination compounds:
\[
\text{Oxidation state of metal}+\text{sum of ligand charges}
=\text{charge on complex}
\]
Covalency of the metal equals the number of coordinate bonds formed with ligands.
Updated On: Jun 22, 2026
- \(5,\,+2\)
- \(6,\,+2\)
- \(5,\,+3\)
- \(6,\,+3\)
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Identify the element \(X\).
The atomic number of the element is \[ 13 \] Atomic number \(13\) corresponds to aluminium (\(Al\)).
Step 2: Determine the covalency of the central metal atom.
The complex is \[ [XCl(H_2O)_5]^{2+} \] Here, the ligands attached to the metal are: \[ 1\,Cl^- \quad \text{and} \quad 5\,H_2O \] Thus, total number of coordinate bonds formed by the metal is \[ 1+5=6 \] Therefore, the covalency of the metal is \[ 6 \]
Step 3: Determine the oxidation state of \(X\).
Let the oxidation state of \(X\) be \(x\).
The charge on the complex ion is \[ +2 \] The charge on ligands: \[ Cl^-=-1 \] \[ H_2O=0 \] Applying charge balance, \[ x+(-1)+5(0)=+2 \] \[ x-1=2 \] \[ x=+3 \]
Step 4: Final conclusion.
Therefore, the covalency and oxidation state of \(X\) are \[ \boxed{6,\,+3} \]
The atomic number of the element is \[ 13 \] Atomic number \(13\) corresponds to aluminium (\(Al\)).
Step 2: Determine the covalency of the central metal atom.
The complex is \[ [XCl(H_2O)_5]^{2+} \] Here, the ligands attached to the metal are: \[ 1\,Cl^- \quad \text{and} \quad 5\,H_2O \] Thus, total number of coordinate bonds formed by the metal is \[ 1+5=6 \] Therefore, the covalency of the metal is \[ 6 \]
Step 3: Determine the oxidation state of \(X\).
Let the oxidation state of \(X\) be \(x\).
The charge on the complex ion is \[ +2 \] The charge on ligands: \[ Cl^-=-1 \] \[ H_2O=0 \] Applying charge balance, \[ x+(-1)+5(0)=+2 \] \[ x-1=2 \] \[ x=+3 \]
Step 4: Final conclusion.
Therefore, the covalency and oxidation state of \(X\) are \[ \boxed{6,\,+3} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET coordination compounds Questions
The correct increasing order for the wavelengths of absorption in the visible region for the following Co$^{3+}$ complexes is:
(i) [Co(NH$_3$)$_6$]$^{3+}$
(ii) [Co(H$_2$O)$_6$]$^{3+}$
(iii) [Co(en)$_3$]$^{3+}$- An element $ X $ (atomic number 13) forms a complex of the type $[XCl(H_2O)_5]^{2+}$. What are the covalency and oxidation state of $ X $ in this complex?
- IUPAC name of [Pt(NH$_3$)$_2$Cl(NH$_2$CH$_3$)]Cl is
- Match the following: List - I \quad (Type of hydride) \quad List - II \quad (Example) A) Electron precise \quad i) SiH$_4$ B) Saline \quad ii) H$_2$O C) Electron deficient \quad iii) MgH$_2$ D) Electron rich \quad iv) B$_2$H$_6$
- Aluminium chloride in acidified aqueous solution gives a complex ion 'X'. The hybridization of central atom in X is
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions