Question:
An element has \(d^5\) configuration. The total number of electron exchanges possible for it is
An element has \(d^5\) configuration. The total number of electron exchanges possible for it is
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For a half-filled \(d^5\) configuration, all five electrons have parallel spins. The total number of exchange pairs is calculated by \(\frac{n(n-1)}{2}\).
Updated On: Jun 18, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Understand the given electronic configuration.
The given configuration is \[ d^5 \] A \(d\)-subshell has five orbitals.
For \(d^5\) configuration, according to Hund's rule, each of the five \(d\)-orbitals contains one electron with parallel spin.
So, the arrangement is \[ d^5 = \uparrow \ \uparrow \ \uparrow \ \uparrow \ \uparrow \]
Step 2: Use the formula for number of electron exchanges.
If \(n\) electrons are present with parallel spins, then the number of possible electron exchanges is \[ \frac{n(n-1)}{2} \] Here, \[ n=5 \] Therefore, \[ \text{Number of exchanges}=\frac{5(5-1)}{2} \] \[ =\frac{5\times 4}{2} \] \[ =10 \]
Step 3: Final conclusion.
Hence, the total number of electron exchanges possible for \(d^5\) configuration is \[ \boxed{10} \]
The given configuration is \[ d^5 \] A \(d\)-subshell has five orbitals.
For \(d^5\) configuration, according to Hund's rule, each of the five \(d\)-orbitals contains one electron with parallel spin.
So, the arrangement is \[ d^5 = \uparrow \ \uparrow \ \uparrow \ \uparrow \ \uparrow \]
Step 2: Use the formula for number of electron exchanges.
If \(n\) electrons are present with parallel spins, then the number of possible electron exchanges is \[ \frac{n(n-1)}{2} \] Here, \[ n=5 \] Therefore, \[ \text{Number of exchanges}=\frac{5(5-1)}{2} \] \[ =\frac{5\times 4}{2} \] \[ =10 \]
Step 3: Final conclusion.
Hence, the total number of electron exchanges possible for \(d^5\) configuration is \[ \boxed{10} \]
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