An aromatic compound $'A'$ having molecular formula ${C7H6O2}$ on treating with aqueous ammonia and heating forms compound $'B'$. The compound $'B'$ on reaction with molecular bromine and potassium hydroxide provides compound $'C'$ having molecular formula ${C_6H_7N}$. The structure of $'A'$ is :
The Correct Option is C
Solution and Explanation
$DU \left( C _{7} H _{6} O _{2}\right)=5$
$DU \left( C _{6} H _{7} N \right)=4$
When $C _{7} H _{6} O _{2}$ reacts with aqueous ammonia and heated it forms $C _{7} H _{7} ON$.Now, $DU \left( C _{7} H _{7} ON \right)=5$
The reagent $Br _{2} / NaOH$ is classic Hoffman Bromamide reagent and this gives a clue that B may be an Amide. This consumes one DU and by seeing remaining 6 carbon and 5 Hydrogens we can say B is Benzamide.
So Benzamide on Hoffman Degradation gives Aniline which matches with the formula of $C$.
We have to know usually $NH _{3}+$ heat gives an Amide when a carboxylic acid is used as a reagent.
So among the options, we can see option C which is a Benzoic acid matches the formula of $X$ and hence is the correct answer.
Top Questions on Amines
- How will you convert nitrobenzene to 2, 4, 6-Tribromo aniline?
- (i) The reaction in which an amide is converted into a primary amine by the action of Br2 and alcoholic NaOH is known as ________.
(ii) How is a primary amine distinguished from a secondary amine using the Hinsberg test? - Write the structures of (A), (B), and (C) in the following reaction:
\[ C_6H_5NO_2 \xrightarrow{Fe/HCl} (A) \xrightarrow[\text{273 K}]{NaNO_2 + HCl} (B) \xrightarrow[\Delta]{H_2O/H^+} (C) \] - What happens when aniline reacts with the following:
(A) Bromine water
(B) $(CH_3CO)_2O$ / Pyridine
(C) $HNO_2 + HCl (0^\circ - 5^\circ C)$ - Why is \(-NH_2\) group of aniline acetylated before carrying out nitration?
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Concepts Used:
Amines
Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.
Amine - Types
Primary Amines:
It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.
Secondary Amines:
Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.
Tertiary Amines:
Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.