Question:

An aperture of size \(a\) is illuminated by a parallel beam of light of wavelength \(\lambda\). The distance at which ray optics has a good approximation is

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Ray optics works when aperture size is large compared to wavelength.
Updated On: May 8, 2026
  • \(\frac{a^2}{\lambda}\)
  • \(\frac{\lambda}{a^2}\)
  • \(\frac{\lambda}{a}\)
  • \(\frac{\lambda^2}{a}\)
  • \(a^2 \lambda\)
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The Correct Option is A

Solution and Explanation

Concept: Ray optics approximation is valid when diffraction effects are negligible.

Step 1:
Understand condition for ray optics.
Diffraction becomes negligible when observation distance is much larger than Fresnel distance.

Step 2:
Fresnel distance formula. \[ z = \frac{a^2}{\lambda} \]

Step 3:
Interpretation.
For distances greater than this, wave effects diminish and ray optics holds.

Step 4:
Conclusion. \[ \boxed{\frac{a^2}{\lambda}} \]
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