Question:
Alkyl halide A (\(C_4H_9Br\)) + NaOH \(\rightarrow\) alcohol (B). Alcohol B + reagent C \(\rightarrow\) carboxylic acid D. What are C and D?
Alkyl halide A (\(C_4H_9Br\)) + NaOH \(\rightarrow\) alcohol (B). Alcohol B + reagent C \(\rightarrow\) carboxylic acid D. What are C and D?
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Jones reagent is a powerful oxidizing agent commonly used to convert primary alcohols into carboxylic acids.
Updated On: Jun 8, 2026
- \([Ag(NH_3)_2]^+\); OH
- PCC; OH
- dil. \(KMnO_4,\ 273K\); OH
- \(CrO_3-H_2SO_4\); OH
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The Correct Option is D
Solution and Explanation
Concept:
Primary alcohols are oxidized to carboxylic acids using strong oxidizing agents.
Step 1: Formation of alcohol B.
Alkyl bromide reacts with NaOH: \[ RBr + NaOH \rightarrow ROH \] Thus B is an alcohol.
Step 2: Select the oxidizing reagent.
PCC is a mild oxidizing agent and stops oxidation at aldehyde stage. Strong oxidizing agents like: \[ CrO_3-H_2SO_4 \] (Jones reagent) oxidize primary alcohols completely into carboxylic acids. Therefore: \[ C = CrO_3-H_2SO_4 \] Hence, the correct option is: \[ \boxed{(D)} \]
Step 1: Formation of alcohol B.
Alkyl bromide reacts with NaOH: \[ RBr + NaOH \rightarrow ROH \] Thus B is an alcohol.
Step 2: Select the oxidizing reagent.
PCC is a mild oxidizing agent and stops oxidation at aldehyde stage. Strong oxidizing agents like: \[ CrO_3-H_2SO_4 \] (Jones reagent) oxidize primary alcohols completely into carboxylic acids. Therefore: \[ C = CrO_3-H_2SO_4 \] Hence, the correct option is: \[ \boxed{(D)} \]
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