Question:
Acetone can be converted into 2-methylpropan-2-ol using
Acetone can be converted into 2-methylpropan-2-ol using
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Grignard reagents add to carbonyls. With formaldehyde, they give 1\(^\circ\) alcohols; with other aldehydes, 2\(^\circ\) alcohols; with ketones, 3\(^\circ\) alcohols.
Updated On: Apr 24, 2026
- Pd H\(_2\)
- B\(_2\)H\(_6\) H\(_2\)O\(_2\), NaOH
- CH\(_3\)MgI H\(_2\)O
- LiAlH\(_4\)
- NaBH\(_4\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
This is a reaction of a carbonyl compound with a Grignard reagent to form a tertiary alcohol.
Step 2: Detailed Explanation:
Acetone is (CH\(_3\))\(_2\)C=O. 2-methylpropan-2-ol is (CH\(_3\))\(_3\)C-OH, a tertiary alcohol with three methyl groups attached to the carbinol carbon. To convert acetone to this alcohol, we need to add one more methyl group. This can be achieved by reacting acetone with methylmagnesium iodide (CH\(_3\)MgI), followed by hydrolysis (H\(_2\)O). The Grignard reagent attacks the carbonyl carbon, and after work-up, we get the tertiary alcohol.
Reducing agents like LiAlH\(_4\) or NaBH\(_4\) would give isopropyl alcohol, not the tertiary alcohol.
Step 3: Final Answer:
The correct reagent is CH\(_3\)MgI H\(_2\)O.
This is a reaction of a carbonyl compound with a Grignard reagent to form a tertiary alcohol.
Step 2: Detailed Explanation:
Acetone is (CH\(_3\))\(_2\)C=O. 2-methylpropan-2-ol is (CH\(_3\))\(_3\)C-OH, a tertiary alcohol with three methyl groups attached to the carbinol carbon. To convert acetone to this alcohol, we need to add one more methyl group. This can be achieved by reacting acetone with methylmagnesium iodide (CH\(_3\)MgI), followed by hydrolysis (H\(_2\)O). The Grignard reagent attacks the carbonyl carbon, and after work-up, we get the tertiary alcohol.
Reducing agents like LiAlH\(_4\) or NaBH\(_4\) would give isopropyl alcohol, not the tertiary alcohol.
Step 3: Final Answer:
The correct reagent is CH\(_3\)MgI H\(_2\)O.
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