Question:
According to Faraday's first law of electrolysis, the mass of substance deposited ($w$) is proportional to
According to Faraday's first law of electrolysis, the mass of substance deposited ($w$) is proportional to
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Remember that in electrolysis problems involving Faraday's laws, the key factor is the quantity of electricity, which combines both current and time.
Updated On: May 31, 2026
- Quantity of electricity ($Q$)
- Current ($I$) only
- Time ($t$) only
- Resistance ($R$)
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Faraday's first law of electrolysis states that the mass of a substance deposited or liberated at any electrode is directly proportional to the quantity of electricity passed through the electrolyte.
Step 2: Meaning
The relationship between the mass of substance ($w$) and the quantity of electricity ($Q$) can be expressed as: \[w \propto Q\]
Step 3: Analysis
To prove that the correct answer is A, we need to understand Faraday's first law. The law states that the mass of a substance deposited or liberated at an electrode during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte. Mathematically, this can be represented as: \[w = kQ\] where $k$ is a constant of proportionality. Let's analyze each option: B) Current ($I$) only - The current alone does not determine the mass deposited; it needs to be multiplied by time to get the quantity of electricity. C) Time ($t$) only - While time is involved in determining the quantity of electricity, as $Q = It$, it is not sufficient on its own without considering the charge passed. D) Resistance ($R$) - Resistance does not directly affect the mass deposited; it influences the current but not the proportionality constant.
Step 4: Conclusion
The correct relationship according to Faraday's first law involves the quantity of electricity, which is a product of current and time. Therefore, the mass of substance deposited is proportional to the quantity of electricity passed through the electrolyte. Final Answer: (A)
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