In a photoelectric effect experiment, light of wavelength \( \lambda \), \( \lambda/2 \), and \( \lambda/6 \) are incident on a metal surface. The stopping potential for these wavelengths are given as \( V_1 \), \( V_2 \), and \( V_3 \), respectively. If the work function of the metal is \( \phi \), calculate the work function using the given wavelengths. The photoelectric equation is given by: \[ E_k = h \nu - \phi \] where:
\( E_k \) is the kinetic energy of the emitted electrons (which is related to the stopping potential),
\( h \) is Planck's constant,
\( \nu \) is the frequency of the incident light,
\( \phi \) is the work function of the metal.
The frequency \( \nu \) is related to the wavelength \( \lambda \) by the equation: \[ \nu = \frac{c}{\lambda} \] where \( c \) is the speed of light.
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,