Question

A weak monobasic acid is \(0.05\ \%\) dissociated in its solution, find the degree of dissociation.

• A. \(2\times 10^{-4}\)
• B. \(4\times 10^{-2}\)
• C. \(5\times 10^{-4}\)
• D. \(2\times 10^{-2}\)

Hint:

Degree of dissociation is the percentage dissociation divided by 100.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
The degree of dissociation \(\alpha\) is the fraction of the acid that ionises. Percent dissociation is \(\alpha\times 100\).

Step 2: Calculation
\(\alpha = \dfrac{0.05}{100} = 5\times 10^{-4}\).

Step 3: Compare the options
The value \(5\times 10^{-4}\) is the third option.

Final Answer:
The degree of dissociation is 5 x 10^-4. \[ \boxed{\text{(C) }5\times 10^{-4}} \]